# How to divide a number in Python ## The challenge

Your task is to create function`isDivideBy` (or `is_divide_by`) to check if an integer number is divisible by each out of two arguments.

A few cases:

```(-12, 2, -6)  ->  true
(-12, 2, -5)  ->  false

(45, 1, 6)    ->  false
(45, 5, 15)   ->  true

(4, 1, 4)     ->  true
(15, -5, 3)   ->  true
```

## Test cases

```Test.describe("Basic Tests")
Test.it("should pass basic tests")
Test.assert_equals(is_divide_by(-12, 2, -6), True)
Test.assert_equals(is_divide_by(-12, 2, -5), False)
Test.assert_equals(is_divide_by(45, 1, 6), False)
Test.assert_equals(is_divide_by(45, 5, 15), True)
Test.assert_equals(is_divide_by(4, 1, 4), True)
Test.assert_equals(is_divide_by(15, -5, 3), True)
```

## Understanding how to solve this

To resolve this problem, we need to understand how to find if a number can be divided without a remainder in Python.

For this we will use Python’s` modulo operator`, (`%`):

```10 % 5  # 0
# if we divide 10 by 5, there is no remainder

10 % 3  # 1
# if we divide 10 by 3, there is a remainder of `1`
```

Therefore, if we say `10 % 5 == 0`, the expression will equal `True`, while the `10 % 3 == 0` will equal False. This is because there is a remainder of `1` in the second instance.

## The solution in Python

Option 1:

```def is_divide_by(number, a, b):
# if can divide without remainder
if number % a ==0 and number % b ==0:
return True
else:
return False
```

Option 2:

```def is_divide_by(number, a, b):
return not (number%a or number%b)
```

Option 3:

```def is_divide_by(n, a, b):
return n%a == 0 == n%b
```
Tags:
0 0 vote
Article Rating
Subscribe
Notify of 