Find the Squares of a Sorted Array in Java

The challenge

Given an array of integers A sorted in non-decreasing order, return an array of the squares of each number, also in sorted non-decreasing order.

Example 1:

Input: [-4,-1,0,3,10]
Output: [0,1,9,16,100]

Example 2:

Input: [-7,-3,2,3,11]
Output: [4,9,9,49,121]

Note:

  1. 1 <= A.length <= 10000
  2. -10000 <= A[i] <= 10000
  3. A is sorted in non-decreasing order.

The solution

class Solution { // return the sorted array squared public int[] sortedSquares(int[] A) { // create a new primitive int array int[] res = new int[A.length]; // loop through the input array for (int i=0; i<A.length; i++) { // square each value res[i] = A[i] * A[i]; } // finally sort the array Arrays.sort(res); // return the array return res; } }
Code language: Java (java)
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